Question

2x⁴+7x³+10x²+21x+72 divide by 2x²-3x+9​

Answer 1

Answer :

x^2+5x+8

please mark as brainiliest

Answer 2

Step-by-step explanation:

Let f(x)=2x

4

−11x

3

+7x

2

+13x−7

Given : (3+

2

) and (3−

2

) are the zeroes of f(x)

So (x−(3+

2

)) and (x−(3−

2

)) are factors of f(x)

and (x−(3+

2

))(x−(3−

2

))=x

2

−6x+7 is a factor of f(x)

Divide f(x) by x

2

−6x+7 we get

set f(x)=0

2x

4

−11x

3

+7x

2

+13x−7=0

(x

2

−6x+7)(2x

2

+x−1)=0

(x−(3−(

2

))(x−(3+

2

))(2x−1)(x+1)=0

x=3−

2

or x=3+

2

or x=

2

1

or x=−1

hence all the zeros of the given polynomial are (−3−

2

),(−3+

2

),

2

1

and−1.