Question

2x4- 7x3- 13x2+63x-45​

Answer 1

what to do...............?????

Answer 2

Step-by-step explanation:

let p of x=2x⁴-7x³-13x²+63x-45

prime factor of constant term 45=1*3*3*5

putting x=1

p(1)=2*1⁴-7*1³-13*1²+63*1-45

=2-7-13+63-45

=65-65

=0

since (x-1)is a factor of p(x)

x-1)2x⁴-7x³-13x²+63x-45(2x³-5x²-18x+45

+2x⁴-2x³

-5x³-13x²

-5x³+5x²

-18x²+63x

-18x²+18x

45x-45

45x-45

0

p(x)=(x-1)[2x³-5x²-18x+45]

=(x-1)x(2x²-5x-18+45)

=x(x-1)(2x²-5x+27)

HOPE THIS HELPS YOU