Question

2x4 +7x3-19x2 -14x+ 30 √2s-2 solve the equation







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Answer 1

Step-by-step explanation:

I hope this will help you

Answer 2

I guess this is what You wanted to write

[ 2x⁴ + 7x³ - 19x² - 14x + 30√2 ] / [ x² - 2 ]

Divide the polynomial with the factor, we get

x² - 2 ) 2x⁴ + 7x³ - 19x² - 14x + 30 ( 2x² + 7x - 15

2x⁴ - 4x²

0 7x³ - 15x² - 14x + 30

7x³ - 14x

0 - 15x² 0 + 30

- 15x + 30

0 0

Factors → (x²-2) (2x²+7x-15)

= (x²-2) (2x²+10x -3x -15)

= (x²-2) [2x(x+5)-3(x+5)]

= (x²-2) (x+5)(2x-3)

= (x +√2) (x -√2) (x+5) (2x-3)

All zeroes → -5 , 3/2 , √2 , -√2