2x⁴+x³-5x²-2x+2 find the roots of this equation
Answers
Answered by
2
Ans :
(+1)(2−1)(2−2)
Step-by-step explanation:
Find one factor BY HIT AND TRIAL .
Factor by grouping
(+1)(23−2−4+2)
.
.
(+1)(23−2−4+2)
(x+1)(2x^{3}-x^{2}-4x+2)(x+1)(2x3−x2−4x+2)
(+1)(23−12−4+2)
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(+1)(23−12−4+2)
(+1)((2−1)⋅2−2(2−1))
.
.
(+1)(2−1)(2−2)
.
.
(+1)(2−1)(2−2)
Answered by
0
Answer:
Step-by-step explanation:
Step 1
((( 2 x (x^3)) - 5x^2) + 4x) -1 = 0
Step 2
(( 2x^3 - 5x^2) + 4x) -1 = 0
Step 3
2x^3 - 5x^2+ 4x-1
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