Question

2xsq. -3х + 1. Find the sum of zeroes and product of zeroes​

Answer 1

Step-by-step explanation:

Let $\alpha$ and $\beta$ be zeroes of $2x^2-3x+1$

if we have a quadratic equation $ax^2+bx+c$

then,

$\alpha + \beta = \frac{-b}{a} \\\alpha \beta = \frac{c}{a}$

Therefore, in this question,

$\alpha + \beta = \frac{-(-3)}{2} = \frac{3}{2}$

$\alpha \beta = \frac{1}{2}$