√2xsq+7x+5x√2=0 find roots of the quadratic equation
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√2 x²+7x +5√2 =0
√2 x² +2x +5x +5√2=0
√2x² +√2 *√2 x + 5x +5√2=0
√2x(x+√2) +5(x+√2)=0
(x+√2)(√2 x+5) =0
therefore
x+√2 =0 or √2 x+5 =0
x= -√2 or x= -5/√2
√2 x² +2x +5x +5√2=0
√2x² +√2 *√2 x + 5x +5√2=0
√2x(x+√2) +5(x+√2)=0
(x+√2)(√2 x+5) =0
therefore
x+√2 =0 or √2 x+5 =0
x= -√2 or x= -5/√2
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