Question

2xsq+x-4=0 completing the square​

Answer 1

Answer:

2x^2+ x -4=0

x^2 + x÷2 -2 =0

x^2 +x/2 = +2 ______1

(1/2× x/2)^2=x^2/16 ________2

add case 2 in both side of case 1

x^2 + x/2 + x^2/16 = +2 +x^2/16

[ x+ x/4]^2= [(32+ x^2)/16]

[ x+ x /4] = +- √[(32+ x^2 /16]

x+ x/4 = +-[√(32+ x^2)]/4

5x/4 = +-[√(32+ x^2)]/4

5x =+-[√(32+ x^2)]

Therefore x= +[√(32+ x^2)]/5

or

x=-[√(32+ x^2)] /5