Question

2xsquaireminusxplusone by eight

Answer 1

Answer:

$2 {x}^{2} - x + \frac{1}{8} = 0$

$16 {x}^{2} - 8x + 1 = 0$

$16 {x}^{2} - 4x - 4x + 1 = 0$

$4x(4x - 1) - 1(4x - 1) = 0$

$(4x - 1)(4x -1) = 0$

$x = \frac{1}{4}$