Math, asked by PhwrwngsatDaimry, 11 months ago

2xsquare+13x+1=0 solved the equation​

Answers

Answered by Anonymous
3

Answer:

2 {x}^{2}  + 13x + 1 = 0 \\multiply \: by2 \\ 4 {x}^{2}  + 26x + 2 = 0 \\  {2x}^{2}  + 2 \times 2x \times  \frac{13}{2}  =  - 2 \\  {2x}^{2}  + 2 \times 2x \times  \frac{13}{2}  +  { (\frac{13}{2} )}^{2}  =  - 2 +  {( \frac{13}{2}) }^{2}  \\  {(2x -  \frac{13}{2} )}^{2}  =  \frac{165}{2}  \\  2x -  \frac{13}{2}  =  \sqrt{ \frac{165}{2} }  \\

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