Math, asked by supergalaxy8114, 11 months ago

2xsquare-2underroot2x +1=0solvewithquadraticformula

Answers

Answered by suvrahore20
1

Answer:

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Answered by rudra09
5

Answer:

⇨2x²-2√2x+1=0

⇨2x²-√2x-√2x+1=0

⇨√2x(√2x-1)-1(√2x-1)=0

⇨(√2x-1)(√2x-1)=0

⇨x=1/√2 , 1/√2

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