Question

√2xsquare+4x+2√2=0 find the value of discriminant

Answer 1

Hiiii friend,

The given equation is ✓2X²+4X+2✓2 = 0

This is in the form of AX²+BX+C = 0 where,


A = ✓2 , B = 4 and C = 2✓2


Therefore,

D = (B²-4AC) = [(4)² - 4 × ✓2 × 2✓2]


=> ( 16 - 8 × ✓2 × ✓2)


=> (16 - 8 × 2)

=> (16-16) = 0


Hence,


The discriminant of the given equation is 0.



HOPE IT WILL HELP YOU....... :-)

Answer 2

We know, discriminant = b² - 4ac

================

Here,
a = √2
b= 4
c = 2√2

Then,
Discriminant = b² - 4ac

=> (4)² - 4(√2)(2√2)

=> 16 - (4×2×2)

=> 16 - 16

=> 0


Discriminant of the given equation is 0

I hope this will help you

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