√2xsquare+5x+√2=0. Find the value of discriminant
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Answer:
Value of the discrinant = 9
Step-by-step explanation:
Compare given Quadratic equation √2x²+5x+√2=0 with ax²+bx+c=0, we get
a = √2 , b = 5 , c = √2
Discreminant (D) = b²-4ac
= 5² - 4×√2×√2
= 25 - 4×4
= 25 - 16
= 9
Therefore,.
Value of the discrinant = 9
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