Question

2xsquare-7x+3=0 find the roots of the question by the method of completing the square .?

Answer 1

hello mate!.....


$given ...... \\ \\ 2x {}^{2} - 7x + 3 = 0 \\ \\ 2x {}^{2} - 6x - x + 3 = 0 \\ \\ 2x(x - 3) - 1(x - 3) = 0 \\ \\ (2x - 1)(x - 3) = 0 \\ \\ 2x - 1 = 0 \: \: and \: x - 3 = 0 \\ \\ x = \frac{1}{2} \: and \: 3 \\ \\ hope \: it \: helps \: u$

Answer 2

$\textbf {Hey there, here is the solution.}$

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This the the completing the square method:

.

2x² - 7x + 3 = 0

Divide by 2 through:

x² - 7/2 x + 3/2 = 0

Subtract 3/2 to both sides:

x² - 7/2 x = - 3/2

Add (b/2)² to both sides:

x² - 7/2 x + (7/4)² = - 3/2 + (7/4)²

Complete the square:

(x - 7/4)² = 25/16

Square root both sides:

x - 7/4 = ± 5/4

Add 7/4 to both sides:

x = 5/4 + 7/4 or x = -5/4 + 7/4

Evaluate RHS:

x = 3 or x = 1/2

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Answer: x = 3 or x = 1/2

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⭐$\textbf {Cheers}$⭐