Question

2xsquare-7xplus3=0 by formula

Answer 1

here

your question is 2x^2-7x+3=0

atfirst you will compare the equation with, ax^2+bx+c=0

where, a=2, b=-7 and c=3

LETS YOU CAN USE,

X= -b plus minus toot over of b^2-4ac/2a.

hope its help you.

Answer 2

Solution :

Compare 2x²-7x+3 = 0 with

ax²+bx+c=0 , we get

a = 2 , b = -7 , c = 3

Discreminant (D)=b²-4ac

= (-7)² - 4×2×3

= 49 - 24

= 25

Quadratic formula :

x = [-b± √D]/(2a)

= [-(-7)±√25]/(2×2)

= ( 7 ± 5 )/5

Therefore ,

x = (7+5)/2 or x = (7-5)/2

=> x = 12/2 or x = 2/2

=> x = 6 or x = 1

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