Question

2xsquare-
$2x {} ^ {2} - \sqrt{3x } - 3$
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Answer 1

2${x}^{2}$ - √3 x - 3 = 0

=> 2${x}^{2}$ - (2√3 + √3)x - 3 = 0

=> 2${x}^{2}$ - 2√3x - √3x - 3 = 0

=> 2x(x - √3) - √3 ( x - √3) = 0

=>(2x - √3)(x - √3) = 0

x = $\frac{ \sqrt{-3} }{2}$ or x = √3