Math, asked by rajbanerjee960, 11 days ago

2xsquare-x+1/8=0 can you help me ​

Answers

Answered by ramchander36
1

Answer:

2x^2-x+1/8=0

by Bhramaguptas quadratic formula,

X=-b+-√b^2-4ac/2a,

a= 2 ,b=-1 , c=1/8

then by substituting values in the equation,

-(-1)+-√1-4(2)(1/8) /2(2)

1+-√1-1/4

1+-√0/4

X = 1/4

Step-by-step explanation:

how's the solution ?

Answered by harshraj29126
0

Answer:

1/4

Step-by-step explanation:

your ans is 1/4

you can solve this by formulas

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