2xsquare-x+1/8=0 can you help me
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Answered by
1
Answer:
2x^2-x+1/8=0
by Bhramaguptas quadratic formula,
X=-b+-√b^2-4ac/2a,
a= 2 ,b=-1 , c=1/8
then by substituting values in the equation,
-(-1)+-√1-4(2)(1/8) /2(2)
1+-√1-1/4
1+-√0/4
X = 1/4
Step-by-step explanation:
how's the solution ?
Answered by
0
Answer:
1/4
Step-by-step explanation:
your ans is 1/4
you can solve this by formulas
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