Question

2xsquare-x-2=0 by formula method

Answer 1

$2 {x}^{2} - x - 2 = 0$
$x = \frac{ - b + - \sqrt{ {b}^{2} - 4ac } }{2a}$
$x = \frac{1 + - \sqrt{ {( - 1)}^{2} - 4(2)( - 2) } }{2(2)}$
$x = \frac{1 + - \sqrt{1 + 16} }{4}$
$x = \frac{1 + - \sqrt{17} }{4}$
$x = \frac{1 + \sqrt{17} }{4} \: or \: x = \frac{1 - \sqrt{17} }{4}$