Math, asked by sriram197819, 6 months ago

(2xsquarey-3y) (3xy-x)

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Answered by prabesh79

1

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Answered by bushrakhan406

1

Answer:

2x^2*y*3xy - 3y*3xy -2x^2*x + 3y*x

= 6x^3y^2 - 9xy^2- 2x^3 + 3yx

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