2xy^ 3 -3y^ 2 1 2 y =\ by factor
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Answer:
You can treat it like a quadratic, where instead of constant numbers, there are
y
terms.
First, find two numbers that multiply to
−
3
(the
c
value of the "quadratic") and add up to
−
2
(the
b
value of the "quadratic").
These two numbers are
−
3
and
1
. Split the middle term into these two numbers. Then, factor the first two and last two terms separately, then combine them:
=
x
2
−
2
x
y
−
3
y
2
=
x
2
+
x
y
−
3
x
y
−
3
y
2
=
x
(
x
+
y
)
−
3
x
y
−
3
y
2
=
x
(
x
+
y
)
−
3
y
(
x
+
y
)
=
(
x
−
3
y
)
(
x
+
y
)
This is the factored form. Hope this helped!
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