Question

2xy + 3x + 2y + 3 regroup terms (factorisation)

Answer 1

Answer:

Rearranging the expression, as 2xy+3x+2y+3

=2xy+2y+3x+3 (these are the two groups)

Comman factor of 1st group = 2y

Comman factor of 2nd group =3

=2y(x+1)+3(x+1)

Now there are two terms, take comman binomial factor (x+1)

= (x+1)(2y+3)