Question

(-2xy) - (3x³y²) (-1/6 x²y⁷)​

Answer 1

Answer:

$= - 2xy - (3 {x}^{3} {y}^{2} )( \frac{ - 1}{6 {x}^{2} {y}^{7} } ) \\ \\ = - 2xy - ( \frac{ - 3 {x}^{3} {y}^{2} }{6 {x}^{2} {y}^{7} } ) \\ \\ = - 2xy - ( \frac{ - 3 {x}^{2} {y}^{2} (x)}{3 {x}^{2} {y}^{2} (2 {y}^{4}) } ) \\ \\ = - 2xy - ( \frac{ - x}{2 {y}^{4} } ) \\ \\ = - 2xy + \frac{x}{2 {y}^{4} } \\ \\ = \frac{ - 2xy \times 2 {y}^{4} + x }{2 {y}^{4} } \\ \\ = \frac{ - 4x {y}^{5} + x }{2 {y}^{4} }$