Question

2xy(9x^2-16y^2)÷4xy(3x+4y) factorise​

Answer 1

Answer:

2xy(9x^2 -16y^2 ÷ 4xy(3x+4y)

2xy[ (3x)^2 - (4y)^2]

Using identity a^2- b^2=( a+b) (a-b)

2xy[ ( 3x+4y) ( 3x-4y)÷4xy( 3x + 4y)

= 1(3x- 4y)÷2

Answer 2

Answer:

the answer is 3x-4y/2xy

Step-by-step explanation:

2xy(9x^2-16y^2)/4xy(3x+4y)

(3x)^2-(4y)^2/2xy(3x+4y)

(3x+4y) (3x-4y)/2xy(3x+4y)

3x-4y/2xy

Hope this helps you

Thanks