Question

(2xyz+y^2z+z^2y)dx +(x^2z+2xyz+xz^2)dy +
(x^2y +xy^2+2xyz)dz=0​

Answer 1

Answer:

555556747chcjxhgzzgjccjxh

Answer 2

Step-by-step explanation:

P = 2xyz + y^2.z + yz^2

Q = x^2.z + 2xyz + xz^2

R = x^2.y + xy^2 + 2xyz

Step 1 : Px + Qy + Rz = I

I = 4xyz(x+y+z)

Integrating factor, IF = 1/I

Step 2 : dI = 4(2xyz + y^2.z + yz^2)dx + 4(x^2.z + 2xyz + xz^2)dy + 4(x^2.y + xy^2 + 2xyz)dz

Step 3 : given equation multiplied by IF * 4

This implies, dI/I = 0

log4(xyz)(x+y+z) = logc

xyz(x+y+z) = c