Question

(2y-1/2y) whole square
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Answer 1

Answer:

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Answer 2

FRom the given question the correct answer is:

the answer $(\frac{2y-1}{2y} )^{2}$ is-1

Given:

$(\frac{2y-1}{2y} )^{2}$

To find:

$(\frac{2y-1}{2y} )^{2}$

Solution:

we will split the square

so,

$=(\frac{2y-1}{2y} )^{2}\\=(\frac{2y-1}{2y} )\times (\frac{2y-1}{2y} )$

$=\frac{4y-1}{4y}$

4y will be canceled

= -1

Hence, the answer $(\frac{2y-1}{2y} )^{2}$ is-1