Question

(2Y-1)/5 - (Y+3)/7 = 0 PLZZZZZZZZZZZZZZ HELPPPPPPPPP

Answer 1

Answer:

$\frac{(2y-1)}{5} -\frac{(y+3)}{7}$ = 0

=> $\frac{2y-1-(y+3)}{35}$  = 0 (35 is taken as LCM and both terms are added

=> $\frac{2y-1-y-3}{35}$ = 0

=> $\frac{y-4}{35}$ = 0

=> $y-4$ = $0*35$ = 0

=> $y = 4$

Therefore, y is equal to 4

Hope it helps!