Question

(2y+1) (y-3)-3y (y+2)=y(2-y)+10. find the value of y.urgent

Answer 1

Step-by-step explanation:

(2y+1)(y-3)-3y(y+2)=y(2-y)+10

(2y+1)(y-3)-3y square - 6y=2y-y square+10

2y(y-3)+1(y-3)-3y square - 6y=2y-y square +10

2y square - 6y+y-3-3y square - 6y=2y-y square +10

-12y+y-3=2y+10

-12y-2y+y=10+3

-13y=13

Y=13/-13

Y=-1

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