(2y+1)(y2-2y3+3y) i want the answer
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Answer:
2y³+y²-2y-1
= y²(2y+1)-1(2y+1)
= (2y+1)(y²-1)
= (2y+1)(y²-1²)
= (2y+1)(y+1)(y-1)
/* By algebraic identity:
a²-b² = (a+b)(a-b) */
Therefore,
2y³+y²-2y-1=(2y+1)(y+1)(y-1)
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