2y=10-y2
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Answer:
2y = 10 – y2
⇒y2+2y=10⇒y2+2y-10=0
So, it is of the form ax2 + bx + c = 0 where a = 1, b = 2 and c = −10
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⇒y2+2y=10⇒y2+2y-10=0
So, it is of the form ax2 + bx + c = 0 where a = 1, b = 2 and c = −10