2y^2+12y-432 factories
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Step-by-step explanation:
As the sum given in the question is not a perfect square, we'll have to use the technique/method of 'splitting the middle term'...
2y² + 12y - 432
Now, we have to multiply the 1st & last term and the answer must be set from the 2nd term by multiplying;
2y² × (-432) = (-864y²)
Now, (-864y²) = 36y × (-24y)....
and, 36y + (-24y) = 12y.....
So, now replace 12y to {36y + (-24)}...
Equation:
2y² + 36y - 24y - 432
= (2y² + 36y) + (-24y - 432)
Take common numbers outside,
= 2y(y + 18) -24 (y + 18)
= (y + 18) (2y - 24)
Here you GO!!!
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