Question

2y^2 27y 13=0 (solve by factorization method)

Answer 1

2y^2 + 27y + 13 = 0

Now multiply the coefficient of y^2 to the constant ,i.e 2 * 13 = 26

y^2 + 27y + 26 = 0

(y + 13) (2y + 1)
y = - 13 or y = -1/2