Question

2y^2 +27y +13 please find the answer​

Answer 1

✯✯ QUESTION ✯✯

${2y}^{2}+27y+13$

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✰✰ ANSWER ✰✰

$⇝{2y}^{2}+27y+13$

$⇝{2y}^{2} + (26y+1y) + 13$

Taking out commons :.

$⇝y (y + 13) + 1 (y + 13)$

$⇝(y + 1 ) (y + 13)$

$⇝y = -1 \:and\: y = -13$

Answer 2

Question:

2y² + 27y + 13 =0

Solution:

By splitting the middle term

2y² + 27y + 13 =0

we get,

=> 2y² + 26y + 1y + 13 =0

=> 2y( y+ 13) + 1(y+ 13) =0

=> (y+13) (2y+1) =0

=> y = -13 , y = -1/2