(2y^2+3x-x^2)+(3x^2-y^2)+(5x^2-3xy)
Answers
Answered by
2
(2y2+3x-x2)+(3x2-y2)+(5x2-3xy)
Final result :
y2 - 3yx + 7x2 + 3x
Step by step solution :
Step 1 :
Equation at the end of step 1 :
((((2•(y2))+3x)-(x2))+((3•(x2))-(y2)))+(5x2-3yx)
Step 2 :
Equation at the end of step 2 :
((((2•(y2))+3x)-(x2))+(3x2-y2))+(5x2-3yx)
Step 3 :
Equation at the end of step 3 :
(((2y2 + 3x) - x2) + (3x2 - y2)) + (5x2 - 3yx)
Step 4 :
Final result :
y2 - 3yx + 7x2 + 3x
Final result :
y2 - 3yx + 7x2 + 3x
Step by step solution :
Step 1 :
Equation at the end of step 1 :
((((2•(y2))+3x)-(x2))+((3•(x2))-(y2)))+(5x2-3yx)
Step 2 :
Equation at the end of step 2 :
((((2•(y2))+3x)-(x2))+(3x2-y2))+(5x2-3yx)
Step 3 :
Equation at the end of step 3 :
(((2y2 + 3x) - x2) + (3x2 - y2)) + (5x2 - 3yx)
Step 4 :
Final result :
y2 - 3yx + 7x2 + 3x
Answered by
5
here is your answer... hhhh
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