Math, asked by shiva222, 1 year ago

(2y^2+3x-x^2)+(3x^2-y^2)+(5x^2-3xy)

Answers

Answered by mangharam
2
 (2y2+3x-x2)+(3x2-y2)+(5x2-3xy) 

Final result :

y2 - 3yx + 7x2 + 3x

Step by step solution :

Step  1  :

Equation at the end of step  1  :

((((2•(y2))+3x)-(x2))+((3•(x2))-(y2)))+(5x2-3yx)

Step  2  :

Equation at the end of step  2  :

((((2•(y2))+3x)-(x2))+(3x2-y2))+(5x2-3yx)

Step  3  :

Equation at the end of step  3  :

(((2y2 + 3x) - x2) + (3x2 - y2)) + (5x2 - 3yx)

Step  4  :

Final result :

y2 - 3yx + 7x2 + 3x
Answered by RendemoShitiri
5
here is your answer... hhhh
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