Question

(2y+3)^2=81 find the root of the Q.E

Answer 1

Ans.

${(2y + 3)}^{2} = 81 \\ or \: \: {(2y + 3)}^{2} - {9}^{2} = 0 \\ or \: \: (2y + 12)(2y - 6) = 0 \\ or \: \: (y + 6)(y - 3) = 0$

So, either y = -6 or y = 3.

I HOPE THAT THIS HELPS YOU.

Answer 2

Here is the answer of your question.

Hope it is useful.

If you satisfied mark it brainliest.