(2y+3)²=81 solve by factorization method
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2
(2y+3)^2=81
Rooting both sides
Then, (2y+3)=9
Then, 2y=9-3
Then, 2y=6
Therefore y=6/3
y=2.
Rooting both sides
Then, (2y+3)=9
Then, 2y=9-3
Then, 2y=6
Therefore y=6/3
y=2.
Answered by
3
4y² + 9 + 12y = 81
4y² + 12y + 9 - 81 = 0
4y² + 12y - 72 = 10
y² + 3y - 18 = 0
y² + 6y - 3y - 18 = 0
y (y + 6) - 3 (y + 6) = 0
(y - 3)(y + 6 ) = 0
y - 3 = 0 => y = 3
y + 6 = 0 => y = -6
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