Math, asked by adityajha130798, 3 months ago

(2y+3)^2 find the suitable identity

Answers

Answered by Flaunt
59

\huge\bold{\gray{\sf{Answer:}}}

Explanation:

Given :

 {(2y + 3)}^{2}

Here,this identity is used:

 \bold{\purple{\boxed{{(x + y)}^{2}  =  {x}^{2}  +  {y}^{2}  + 2xy}}}

 {(2y + 3)}^{2}  =  {(2y)}^{2}  +  {(3)}^{2}  + 2(2y)(3)

 =  > 4 {y}^{2}  + 9 + 12y

\bold\fcolorbox{aqua}{orange}{Answer} 4 {y}^{2}  +  12y+9

ㅤㅤㅤㅤㅤㅤㅤ

____________________________________________

Other Identity related to this :

\bold{\boxed{ {(x -y)}^{2}  =  {x}^{2}  +  {y}^{2}  - 2xy}}

\bold{\boxed{ {x}^{3}   +   {y}^{3}  =  {x}^{3}  +  {y}^{3}   + 3xy(x + y)}}

\bold{\boxed{(x + y)(x  + z) =  {x}^{2}  + (y+ z)x + yz}}

\bold{\boxed{ {(x +y)}^{3}  =  {x}^{3}  +  {y}^{3}  +3xy[x+y]}}

Answered by Anonymous
0

\huge\bold{\gray{\sf{Answer:}}}

Explanation:

Given :

 {(2y + 3)}^{2}

Here,this identity is used:

 \bold{\purple{\boxed{{(x + y)}^{2}  =  {x}^{2}  +  {y}^{2}  + 2xy}}}

 {(2y + 3)}^{2}  =  {(2y)}^{2}  +  {(3)}^{2}  + 2(2y)(3)

 =  > 4 {y}^{2}  + 9 + 12y

\bold\fcolorbox{aqua}{orange}{Answer} 4 {y}^{2}  +  12y+9

ㅤㅤㅤㅤㅤㅤㅤ

____________________________________________

Other Identity related to this :

\bold{\boxed{ {(x -y)}^{2}  =  {x}^{2}  +  {y}^{2}  - 2xy}}

\bold{\boxed{ {x}^{3}   +   {y}^{3}  =  {x}^{3}  +  {y}^{3}   + 3xy(x + y)}}

\bold{\boxed{(x + y)(x  + z) =  {x}^{2}  + (y+ z)x + yz}}

\bold{\boxed{ {(x +y)}^{3}  =  {x}^{3}  +  {y}^{3}  +3xy[x+y]}}

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