2y/3 - 2 = -y +1 . Please solve using systematic method. Class 6 Solution also.
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Explanation:
Suppose that gcd(2n+1,9n+4)≠1 and there exist a d such that gcd(2n+1,9n+4)=d.
Now d|9n+4, and d|2n+1 ⟹d|9n+4−4×(2n+1).
⟹d|n.
d|2n+1−n⟹d|n+1.
Again: d|n+1−n⟹d|1.
It is enough I think
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