Question

2y -3 = 3 by 10 (5y -12) find value of x

Answer 1

Answer: 2y-3 = 3/10 (5y-12)

= 2y-3 = 3y/2 - 18/5

= 2y-3y/2 = -18/5+3

= 4y-3y/2 = -18+15/3

= y = -3/3 × 2

= y = -2

Answer 2

Answer:

There is no x in the question......but

2y - 3 = 3 /{ 10( 5y - 12 )}

( 5y - 12 ) * (2y - 3) = 3/10

10 y^2 - 15 y - 24y + 36 = 3/10

10 y^2 - 39y + 36 = 3/10

10 y^2 - 39y+ 36 - 3/10 =0

100y^2 - 390y + 360 -3 =0

100y^2 - 390y + 357 =0

y = (39 + √93 )/20 ,  (39 - √93 )/20  (answer )

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