Question

2y/3+4/9= 7/3 please give me solutions​

Answer 1

Answer:

thisis your answer

Step-by-step explanation:

=17/6

Answer 2

Given:

The equation:-

$\sf{\dfrac{2y}{3} + \dfrac{4}{9} = \dfrac{7}{3}}$

What To Find:

We have to solve and find the value of y.

Solution:

$\sf{\dfrac{2y}{3} + \dfrac{4}{9} = \dfrac{7}{3}}$

Find the LCM of 3 and 9 ie 9,

⇒ $\sf{\dfrac{2y \times 3}{3 \times 3} + \dfrac{4 \times 1}{9 \times 1} = \dfrac{7 \times 3}{3 \times 3}}$

Multiply in both sides,

⇒ $\sf{\dfrac{6y}{9} + \dfrac{4}{9} = \dfrac{21}{9}}$

Take 4 by 9 to RHS,

⇒$\sf{\dfrac{6y}{9} = \dfrac{21}{9} - \dfrac{4}{9}}$

Subtract 21/9 by 4/9,

⇒ $\sf{\dfrac{6y}{9} = \dfrac{17}{9}}$

Use cross multiplication,

⇒ 9 (6y) = 9 (17)

Multiply the both side,

⇒ 54y = 153

Take 54 to RHS,

⇒ $\sf{y = \dfrac{153}{54}}$

Divide 153 by 54,

⇒ $\sf{y = \dfrac{17}{6}}$

∴ So, the value of y of the given equation is $\sf{\bf{\dfrac{17}{6}}}$.