Question

2y^3 + 5 y ^ 2 + 4y + 1 in factorization of cubic polynomials​

Answer 1

$\star\bold\pink{Answer:-}$

$\implies$2y³ + 5y² + 4y + 1 = 0

$\implies$y²(2y+5) +1(4y+1) = 0.

$\implies$(y²+1) (2y+5) (4y+1) = 0