Question

(2y+3)(6y-7)=(3y-2)(4y+5)​

Answer 1

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$12 {y}^{2} - 14y + 18y - 21 = 12 {y}^{2} + 15y - 8y - 10$

$4y - 21 = 7y - 10$

$4y - 7y = 21 - 10$

$- 3y = 11$

$y = - \frac{11}{3}$

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Answer 2

Answer:

-11/3

Step-by-step explanation:

(2y+3)(6y-7)=(3y-2)(4y+5)​

= 12y^2 - 14y + 18y - 21 = 12y^2 + 15y - 8y -10

= 12y^2 + 4y - 21 = 12y^2 + 7y - 10

= 4y - 21 = 7y - 10

= -3y = 11

= y= -3/11

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