Question

2y-3<=17y-4<=-4, y belongs to R.
I've got the solution set correct but in answer along with the solution set it says *null* ! . How ?

Answer 1

◀HERE'S ⏬ YOUR ANSWER▶

Taking the 1st two terms, we get
$2y - 3 \leqslant 17y - 4 \\ or \: \: - 3 + 4 \leqslant 17y - 2y \\ or \: \: 1 \leqslant 15y \\ or \: \: 15y \geqslant 1 \\ or \: \: y \leqslant \frac{1}{15}$

Taking the last two terms, we get
$17y - 4 \leqslant - 4 \\ or \: \: 17y \leqslant - 4 + 4 \\ or \: \: 17y \leqslant 0 \\ or \: \: y \geqslant 0$

So we get a solution set
$0 \leqslant y \leqslant \frac{1}{15}$

⏏HOPE THIS ⬆ HELPS YOU⏏