Math, asked by tabiya47, 1 year ago

2y-3(y+1)=5y-7 solve the equation and check​

Answers

Answered by Siddharta7
4

2y-3(y+1)=5y-7

We move all terms to the left:

2y-3(y+1)-(5y-7)=0

We multiply parentheses

2y-3y-(5y-7)-3=0

We get rid of parentheses

2y-3y-5y+7-3=0

We add all the numbers together, and all the variables

-6y+4=0

We move all terms containing y to the left, all other terms to the right

-6y=-4

y=-4/-6

y=2/3

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