Question

2y+3/y-9=2/7 pls answer this equation​

Answer 1

Step-by-step explanation:

(2y+3)/y-9=2/7

We move all terms to the left:

(2y+3)/y-9-(2/7)=0

Domain of the equation: y!=0

y∈R

We add all the numbers together, and all the variables

(2y+3)/y-9-(+2/7)=0

We get rid of parentheses

(2y+3)/y-9-2/7=0

We calculate fractions

(14y+21)/7y+(-2y)/7y-9=0

We multiply all the terms by the denominator

(14y+21)+(-2y)-9*7y=0

Wy multiply elements

(14y+21)+(-2y)-63y=0

We get rid of parentheses

14y-2y-63y+21=0

We add all the numbers together, and all the variables

-51y+21=0

We move all terms containing y to the left, all other terms to the right

-51y=-21

y=-21/-51

y=7/17