Question

2y – (3y + 2) – 6+ (3y - 8)​

Answer 1

Answer:

2y-16

Step-by-step explanation:

Answer 2

$2y-(3y+2)=6+(3y-8)$

$2y-(3y+2)-(6+(3y-8))=0$

$2y-3y-(6+(3y-8))-2=0$

$6+(3y-8)$

$3y-8+6$

$3y-2$

$-(3y-2)$

$-1y-(3y-2)-2=0$

$-1y-3y+2-2=0$

$-4y=0$

$y=0/-4$

$y=0$