Question

2y^4-18x^2y^2-48x^2y-32y^2​

Answer 1

Step-by-step explanation:

2y^4-18x^2y^2-48x^2y-32y^2​

= (((2•(y^4))-((18•(x^2))•(y^2)))-(48x•(y^2)))-2^5y^2

= (((2•(y^4))-((18•(x^2))•(y^2)))-(2^4•3y^2x))-2^5y^2

= (((2•(y^4))-((2•3^2x^2)•y^2))-(2^4•3y^2x))-2^5y^2

= ((2y^4 -  (2•3^2y^2x^2)) -  (2^4•3y^2x)) -  2^5y^2

= 2y^4 - 18y^2x^2 - 48y^2x - 3^2y^2  =    2y^2 • (y^2 - 9x^2 - 24x - 16)