Math, asked by awanateena2867, 11 months ago

(2y-4)(3y-1)=(2y+1)(2y-1)

Answers

Answered by mannu1315
2

Answer:

(2y-4)(3y-1)=(2y+1)(2y-1)

2y(3y-1)-4(3y-1)=2y(2y-1)+1(2y-1)

6y^2-2y-12y+4=4y^2-2y+2y-1

6y^2-14y+4=4y^2-1

6y^2-4y^2-14y+4+1=0

2y^2-14y+5=0

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