2y-4/3y-2=-2/3find y
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Answered by
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Answer:
2y-4/3y-2=-2/3
by cross multiplying
3(2y-4) =-2(3y-2)
6y-12=-6y+4
6y+6y=4+12
12y=16
y=16/12
y=8/6=4/3
y=4/3
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