Math, asked by barikmonalisa832, 8 months ago

2y^4+7y^2+8y^3+4y+^3 / y+3​

Answers

Answered by Anonymous
0

Answer:

y+3=9 y=-3

p(-3)=2×(-3)^4+7(-3)^2+8(-3)^3+4(-3)+3

=2×81+7×9+8×-27-12+3

=162+72-216-12+3

=237-228=11

so p(-3)=11 so remainder is 11

Step-by-step explanation:

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