Question

(2y+5) (2y+5) identities

Answer 1

Answer:

hope it help you

Step-by-step explanation:

(2x+5)(2y+5)

=(2x×2y+5×2y+5×2x+5×5)

=(4xy+10x+10y+25)

Answer 2

Answer:

Solution:-

• First write the given polynomial

$\qquad{:}\longrightarrow$$\sf (2y+5)(2y+5)$

• Simplify

$\qquad{:}\longrightarrow$$\sf (2y+5)^2$

• Use algebraic identitie

${\boxed{\sf (a+b)^2=a^2+2ab+b^2 }}$

• Substitute the values

$\qquad{:}\longrightarrow$$\sf (2y)^2+2×2y×5+(5)^2$

• Simplify

$\qquad{:}\longrightarrow$$\sf 4y^2+20y+25$

$\therefore\sf (2y+5)(2y+5)=4y^2+20y+25.$