Question

2y+5/y+7=1. Sove the equation​

Answer 1

$\sf\large\underbrace[Question:-]$

$2y + \frac{5}{y} + 7 = 1$

${\huge{\boxed{\mathcal{\pink{Answer \: }}}}}$

$2y + \frac{5}{y} + 7 = 1$

$\frac{y.2y}{y} + \frac{5}{y} + \frac{y.7}{y} = 1$

$\frac{y.2y + 5 + y.7}{y} = 1$

$\frac{2yy + 5 + y.7}{y} = 1$

$\frac{ {2y}^{2} + 5 + y.7 }{y} = 1$

$\frac{ {2y}^{2} + 5 + 7y}{y} = 1$

$\frac{ {2y}^{2} + 7y + 5 }{y} = 1$

$y( \frac{ {2y}^{2} + 7y + 5}{y} ) = y$

${2y}^{2} + 7y + 5 = y$

${2y}^{2} + 7y + 5 - y = 0$

${2y}^{2} + 6y + 5 = 0$

_____________________________________________

USING QUADRATIC FORMULA:-

$y = \frac{ - b± \sqrt{ {b}^{2} - 4ac } }{2a }$

_____________________________________________

$y = \frac{ - 6± \sqrt{ {6}^{2} - 4.2.5 } }{2.2}$

$y = \frac{ - 6± \sqrt{ - 4} }{4}$

$d = - 4$